1.5x^2-0.5=0

Solution for 1.5x^2-0.5=0 equation:

1.5x^2-0.5=0

a = 1.5; b = 0; c = -0.5;
Δ = b2-4ac
Δ = 02-4·1.5·(-0.5)
Δ = 3
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3}}{2*1.5}=\frac{0-\sqrt{3}}{3}
=-\frac{\sqrt{}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3}}{2*1.5}=\frac{0+\sqrt{3}}{3}
=\frac{\sqrt{}}{3}
$